Question

The sum of 6 consecutive integers is 519. What is the third number in this sequence?

Answer 1

Let the third number be n. then the series of numbers is n-2, n-1, n, n+1, n+2, n+3. The sum of these numbers should be 519. Add them together and solve for n:
n-2+n-1+n+n+1+n+2+n+3=519
6n+3=519
6n=516
n=86

So the third number is 86.

Answer 2

the third integer is 86, hope this helps :)