Question

What is the value of q when the solution contains 2.50×x10−3 m mg2+ and 2.00×10−3m co32−?

Answer 1

The correct answer is: Q =
`5.0 * 10^(-6)`

Step-by-step explanation:

The chemical equation is:

`MgCO_3 \to Mg^(2+) + CO_3^(2-)`

The value of Q can be obtained as follows:

Q = [
`Mg^(2+)`][
`CO_3^(2-)`]
Q = [2.50×x10^−3][2.00×10^−3]
Q =
`5.0 * 10^(-6)`