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Two small objects each with a net charge of +q exert a force of magnitude f on each other: we replace one of the objects with another whose net charge is +4q: the original magnitude of the force on the +q charge was f; what is the magnitude of the force on the +q charge now?

User Magdala
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2 Answers

3 votes
the correct answer is 672
User Sachin Pangare
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4 votes
The force between 2 charged objects is given by, F = kq1q2/d².
where k ⇒ constant
d ⇒ distant between the 2 objects.

In this case, k and d are constants.
So, let k/d² = x
since q1=q2,
F = xq²
x = F/q²
After replacing q1 with 4q, the new force on +q will be:

F = xq.4q
= Fq4q/q²
= 4F

The new charge on +q is 4F.

User Rajax
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