Question

A gas sample occupies 3.50 liters of volume at 20.°c. what volume will this gas occupy at 100°c (reported to three significant figures)?

Answer 1

Based on Charle's Law, we have

`(V1)/(V2) = (T1)/(T2)`
where, V and T are volume and temperature respectively.

Now, given that, V1 = 3.5 L, T1 =
`20 ^(0)C` = 293 K and T2 =
`100^(0)C` = 373 K

∴ V2 =
`((T2)X(V1))/(T1) = (373 X 3.5)/(293) = 4.556l`