Question

How many moles of potassium hydroxide are needed to complete neutralize 1.50 moles of sulfuric acid (h2so4). please show all work. 2koh + h2so4 -> k2so4 + 2h2o?

Answer 1

The balanced equation for the reaction is
2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

The stoichiometric ratio between KOH and H₂SO₄ is 2 : 1

The moles of Sulfuric acid = 1.5 mol

moles of KOH / moles of H₂SO₄= 2 / 1
moles of KOH / 1.5 mol = 2
moles of KOH = 2 x 1.5 mol = 3.0 mol

Hence, 3.0 moles of KOH are needed to neutralize the given H₂SO₄ acid