The balanced equation for the reaction is
2KOH + H₂SO₄ → K₂SO₄ + 2H₂O
The stoichiometric ratio between KOH and H₂SO₄ is 2 : 1
The moles of Sulfuric acid = 1.5 mol
moles of KOH / moles of H₂SO₄= 2 / 1
moles of KOH / 1.5 mol = 2
moles of KOH = 2 x 1.5 mol = 3.0 mol
Hence, 3.0 moles of KOH are needed to neutralize the given H₂SO₄ acid