Question

Factor the trinomial below.

6x2 – 9x – 6

A. 3(2x + 1)(x – 6)
B. 3(2x + 2)(x – 1)
C. 3(2x + 1)(x – 2)
D. 3(2x + 6)(x – 1)

Answer 1

C. 3(2x+1)(x-2)

Explanation:

To factor the trinomial 6x² - 9x -6, we will follow the steps below;

First, 3 is common among the three numbers, so we will start by factoring out 3, so that the expression becomes;

3(2x² - 3x - 2)

We will now proceed to factorize; 2x² - 3x - 2

Find two numbers such that its product gives -4 and its sum gives -3.

Such number is -4 and 1

-4 × 1 = -4

-4 + 1 = -3

We will replace -3x by -4x + x in the above expression

2x² - 4x + x - 2

(2x² - 4x) (+x - 2)

In the first parenthesis, 2x is common, so we will factor out 2x while in the second parenthesis 1 is common, so we will factor out 1. Hence;

2x(x - 2) + 1(x-2)

(2x+1)(x-2)

3(2x² - 3x - 2) = 3(2x+1)(x-2)

6x² – 9x – 6 = 3(2x+1)(x-2)

Therefore the factorized form of 6x² – 9x – 6 is 3(2x+1)(x-2)

Answer 2

For this case we have the following trinomial:
6x2 - 9x - 6
Rewriting we have:
3 (2x2 - 3x - 2)
Factoring we have:
3 (2x + 1) (x-2)
Answer:
The factored expression for this case is given by:
C. 3 (2x + 1) (x - 2)