Question

A certain part of the electromagnetic spectrum ranges from 200 nm to 400 nm. what is the lowest frequency associated with this portion of the spectrum? (c 3.00 108 m/s)

Answer 1

The lowest and highest wavelengths of this part of the electromagnetic spectrum are:

`\lambda_1 = 200 nm=200 \cdot 10^(-9) m`

`\lambda_2 = 400 nm = 400 \cdot 10^(-9) m`

We can calculate the corresponding frequencies by using:

`f= (c)/(\lambda)`
where c is the speed of light. If we use this equation, we find:

`f_1 = (c)/(\lambda_1)= (3 \cdot 10^8 m/s)/(200 \cdot 10^9 m) =1.5 \cdot 10^(15)Hz`

`f_2 = (c)/(\lambda_2)= (3 \cdot 10^8 m/s)/(400 \cdot 10^9 m) =7.5 \cdot 10^(14)Hz`
Therefore, the lowest frequency associated with this portion of the spectrum is

`f_2 = 7.5 \cdot 10^(14) Hz`