Question

Plz help and explain thanks

Answer 1

hey there!:


for q = - 6 and x = 5 :

5⁰
------
(-6)⁻³


Apply rule : a⁰ = 1 , a≠0

5⁰ = 1 :

1
* -------
(-6)⁻³


Apply exponent rule: (-a)ⁿ = - aⁿ , if " n " is odd :

(-6)⁻³ = -6⁻³


1
* -------
-6⁻³


Apply fraction rule : a/-b = - a/b


= - 1 / -6⁻³

Apply exponent rule: a⁻ᵇ = 1 / ab


6⁻³ = 1 / 6³

=> ( - 1/1 ) / ( 6³ )

= - 6³ / 1

Apply rule a/1 = a

= - 6³

* 6 * 6 * 6 => 216

a = -216

hope this helps!

Answer 2

`(x^0)/(q^(-3)) = (5^0)/((-6)^(-3))= (1)/((-6)^(-3)) = (-6)^3 = -216`