Question

What is the total resistance of three 6-ohm resistors hooked in parallel

Answer 1

The equivalent resistance of n resistors in parallel is given by

`(1)/(R_(eq))= (1)/(R_1)+ (1)/(R_2)+...+ (1)/(R_n)`

In this case, we have three resistors of
`6 \Omega` each, so their equivalent resistance when they are connected in parallel is

`(1)/(R_(eq))= (1)/(6 \Omega)+ (1)/(6 \Omega)+ (1)/(6 \Omega)= (3)/(6 \Omega)`
Which gives

`R_(eq)= (6 \Omega)/(3)=2 \Omega`