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What is the height of a triangle that has an area of 60 yd squared and a base with a length of 12 yd

User Naome
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2 Answers

2 votes
The answer is: " 10 yd. " .
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The height of the triangle is: " 10 yd " .
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Step-by-step explanation:
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The formula for the area, "A", of a triangle is:

→ " A = (b * h) / 2 " ;

in which: " A = area (in square units; in this case; "yd² " ;

= " 60 yd² " {given} ;

"b = base length = 12 yd" {given} ;

"h = [perpendicular] height ; for which we shall solve;
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→ A = (b * h) / 2 ;

→ Rearrange the equation to isolate "h" on one side of the equation; since we need to solve for "h" (height) ;

→ Multiply each side of the equation by "2" ;

→ 2 * A = 2 * [ (b * h) / 2 ] ;

to get:

→ 2A = b * h ;

↔ b * h = 2A ;

Divide each side of the equation by "b" ;
to isolate "h" on one side of the equation;

→ (b * h) / b = 2A / b ;

→ h = 2A / b ;

Now, plug in our given values for "A" and "b" ;
to solve for "h" ;

→ h = (2* 60 yd²) / (12 yd) ;

= (120 yd²) / (12 yd).

= 10 yd.

→ h = 10 yd.
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The answer is: " 10 yd. " .
_______________________________________________________
The height of the triangle is: " 10 yd " .
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User DenFav
by
6.1k points
5 votes
the answer would be 0.4yd
User Sabumnim
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6.0k points