Answer: The correct answer is Option A.
Step-by-step explanation:
Iodine is the 53rd element of the periodic table. The number of electrons present in this element are 53.
The electronic configuration of this element =
![[Kr]4d^(10)5s^25p^5](https://img.qammunity.org/2019/formulas/chemistry/middle-school/g6g0s8dxya99wc0pvjzuvmb464zqx8t2mv.png)
As, the electrons are filled in the orbitals having n = 5. So, it is present in Period 5.
And, the number of valence electrons of this element is 7. So, it is present in Group 17.
Hence, the correct answer is Option A.