Question

Base your answer to the question on the diagrams shown below.

What is the probability of drawing a red card and then spinning a 1?

Answer 1

The probability of drawing a red card and spinning a 1 are independent events, thus to get the probability of them occurring at the same time we shall have:
P(Red)×P(Spinning 1)
P(Red)=2/5
P(Spinning 1)=4/8=1/2
Thus:
P(Red)×P(Spinning 1)=1/2×2/5=1/5

Answer 2

Answer:
`(1)/(5)`

Explanation:

From the given picture, the total number of cards = 5

The number of red card = 2

Thus, the probability of drawing a red card P(red)=
`(2)/(5)`

Also, total number of digits on spinner = 8

Number of 1's=4

Thus, the probability of spinning a 1 P( spinning 1)=
`(4)/(8)=(1)/(2)`

Since both the events of drawing a red card and spinning a 1 are independent events, therefore, the probability of drawing a red card and then spinning a 1=
`\text{ P(red)}*\text{P( spinning 1)}=(2)/(5)*(1)/(2)=(1)/(5)`