Question

a 920-g empty iron kettle is out on a hot stove. how much heat must the kettle absorb to raise its temperature 15.0 Celsius to 93.0 celsius the especific heat capacity iron is 470 j/kg * k

Answer 1

Heat absorbed, Q is given by;

Q = mCΔT, where m = mass of kettle = 920 g = 0.92 kg; C = Specific heat capacity = 420 J/kg.K, ΔT = change in temperature = 93-15 =78 K

Substituting;
Q = 0.92*420*78 = 30,139.2 J