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1 vote
Solve the system of equations given below.
8x+4y=16
7y=15-x

User Denisa
by
8.4k points

1 Answer

6 votes
1) first slove for X ( 7y=15−x) to solve this first subtract 15 from both sides -->
7y-15= -X ---> then multiply by -1 on both sides -----> -7y+15=x ( switch sides) so basically : x=−7y+15
2) Then
Substitute x=-7y+15x=−7y+15 into 8x+4y=16 now solve steps below how to solve:
Start with the original equation ( 8x+4y=16)
Let x= -7y+15
8(−7y+15)+4y=16 ----> simplify ----> −52y+120=16
Now solve for Y (
−52y+120=16) steps:
−52y=16−120 ( subtract 120 from both sides) & simplify by 16-120=−104
−52y=−104
now isolate Y divide both sides by -52 ----> y=2
Substitute y=2 into x=-7y+15
x= -7(2)+15
x=1
your final answer :
x=1
y=2

User NewlessClubie
by
8.4k points

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