Question

calculate the volume of titrant required to reach the endpoint. calculate the volume in ml of a 0.200 m naoh solution needed to neutralize 345 ml of 0.0333 m c₆h₈o₇ standard solution.

Answer 1

The volume of NaOH solution required to neutralize 345 mL of a 0.0333 M C6H8O7 standard solution is approximately 57.375 mL.

Step-by-step explanation:

In a titration, the volume of titrant required to reach the endpoint can be calculated using the formula:

Titrant Volume (mL) = (Volume of Standard Solution (mL) * Molarity of Standard Solution) / Molarity of Titrant

Applying this formula to the given question, the volume of NaOH solution required to neutralize 345 mL of 0.0333 M C6H8O7 standard solution can be calculated as follows:

Titrant Volume (mL) = (345 mL * 0.0333 M) / 0.200 M = 57.375 mL

Therefore, the volume of NaOH solution required is approximately 57.375 mL.