Question

The frequency of A4 is 440.00 Hz.
what is the frequency of A6, which is two octaves above A4?

Answer 1

The formula for getting the unknown frequecy is given by, (2∧n)×f.
Where n ⇒the number of octavos above A4 and
f ⇒the given frequency

So, the frequency of A6 is calculated as follows.

Frequency = (2∧2)×440.00
= 1760.00 Hz

Answer 2

To solve this problem you must apply the proccedure shown below:

1. You have the following information given in the problem above: The frequency of A4 is 440.00 Hz.

2. So, you must apply the following formula to calculate the frequency of A6, which is two octaves above:

(2^n)f

Where n is the octaves above and f is the known frequency.

3. Therefore, you have:

A6=(2^n)f
A6=(2^2)(440.00 Hz)
A6=1760 Hz

Therefore, the answer is: A6=1760 Hz.