Question

The formation of an ionic bond involves a number of different processes. in the formation of sodium chloride, represented by the equation given below, two steps result in a release of energy. choose those two steps. (yes, you fill in two bubbles on your scantron for this question. you must choose both correct answers to receive credit for the question.) 2na(s) + cl2(g) → 2nacl(s)

a. attraction of na+ and cl– to form nacl.
b. removal of an electron from na.
c. the addition of an electron to each cl atom
d. conversion of na(s) to na(g).
e. dissociation of cl2 to form 2 cl atoms.

Answer 1

In the formation of sodium chloride, two steps result in a release of energy: attraction of Na+ and Cl- to form NaCl, and the conversion of Na(s) to Na(g) as the sodium atom donates an electron to chlorine atoms.

Step-by-step explanation:

The formation of an ionic bond involves the transfer of electrons from one atom to another. In the case of sodium chloride (NaCl), two steps result in a release of energy. The first step is the attraction of Na+ and Cl- ions to form NaCl. The second step is the conversion of Na(s) to Na(g) as the sodium atom donates an electron to chlorine atoms.

Answer 2

Answer:
The two steps which results in the release of energy are;

A) Attraction of Na⁺ and Cl⁻ to form NaCl

C) The addition of an electron to each Cl atom

Step-by-step explanation:
As we know Born Haber Cycle is helpful in measuring the Lattice Energies of Crystal systems indirectly. So, the formation of NaCl crystal takes place in several steps. Among all steps, The formation of Chloride ions (Electron Affinity) and binding of Na⁺ and Cl⁻ (Lattice Energy) are exothermic in nature, while remaining all steps require energy to proceed (Endothermic).