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If 25.0 ml of seawater has a mass of 25.895 g and contains 1.295 g of solute, what is the mass/mass percent concentration of solute in the seawater sample? 5.18% 5.001% 3.862% 96.5% 20.00%
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If 25.0 ml of seawater has a mass of 25.895 g and contains 1.295 g of solute, what is the mass/mass percent concentration of solute in the seawater sample? 5.18% 5.001% 3.862% 96.5% 20.00%

User AMunim
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The % mass/mass concentration of solute in the seawater sample is calculated as below


% mass = mass of the solute /mass of the solvent(sea water) x100
mass of the solute =1.295 g
mass of the solvent(sea water_) = 25.895 g

there the % mass = 1.295/25.895 x100 = 5.001 %
User Bettinna
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