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How many grams of argon would it take to fill a light bulb with a volume of 0.475 l at stp?

User Pfych
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STP stands for Standard Temp. and Pressure.
Standard Temp. = 273.15 K
Pressure = 1 atm
Now, ideal gas equation we know that PV = nRT
where, V = volume of gas = 0.475 l
R = universal gas constant = .082507 l atm mol-1 K-1

∴ n =
(PV)/(RT)
∴ n =
(1 X .475)/(0.082057X 273.15)
∴n = 0.02112 mol

Thus, number of moles of Ar present = 0.02112

But, number of mole =
(wt. of .substance )/(At./Mol. Weight)
In present case, weight of Ar (g) = number of mole of Ar X Atomic Wt. of Ar
∴ weight of Ar = 40 X 0.02112 = 0.8477 g
User Medin Piranej
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