Question

Determine the pressure exerted by 2.50 mol of gas in a 2.92 l container at 32 oc.

Answer 1

I guess you meant "at
`32^(\circ)C`"

Solution:
we can solve the problem by using the ideal gas law, which states:

`pV=nRT`
where
p is the gas pressure
V its volume
n the number of moles
R the gas constant
T the absolute temperature

Before using this equation, we have to convert the temperature in Kelvin:

`T=32^(\circ)C+273 = 305 K`
and the volume in
`m^3`:

`V=2.92 L= 2.92 dm^3 = 2.92 \cdot 10^(-3) m^3`

So now we can re-arrange the ideal gas equation to find the pressure exerted by the gas, p:

`p= (nRT)/(V)= ((2.50 mol)(8.31 J/mol K)(305 K))/(2.92 \cdot 10^(-3) m^3)= 2.17 \cdot 10^7 Pa`