Question

Question 3 given that au-197 is the only natural isotope of gold, what is the mass of one au atom and the mass of avogadro's number of au atoms, respectively? 196.97 g and 196.97 amu 197 amu and 197 g 197 g and 197 amu 196.97 amu and 196.97 g none of the above

Answer 1

Step-by-step explanation:

The mass number of an element is a weighted average of all the isotopes of that element.

If Au has only one isotope then the atomic weight of that isotope matches the mass number.

Au-197 ==> mass number 197

Mass of one atom=mass number 197 amu

Mass of one mol of atoms:

`m=197 amu*1.66054*10^(-24)g/amu*6.022*10^(23)`

`m=196.97 g`

Answer 2

The mass of one Au atom is 196.97 amu from periodic table and the mass of Avogadro's number of Au atoms is 196.97 g due to this is the mass of one mole of gold