Question

What is the molarity of 500 ml of a solution containing 85.0g AgNO3?

Answer 1

1.0 M, if you're just looking for an answer.

Formula mass of AgNO3 is 107.9 + 14 + (3 X 16) = 169.9 g.

85.0 g 0.5 mole
------- = ------------ = 1.0 M
169.9 (g/mole) 0.5 liter

Answer 2

Answer: 1 M

Step-by-step explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

`Molarity=(n* 1000)/(V_s)`

where,

n= moles of solute

`Moles=\frac{\text{Given mass}}{\text{Molar mass}}=(85.0g)/(170g/mol)=0.5moles`

`V_s` = Volume of solution in ml

Now put all the given values in the formula of molarity, we get

`Molarity=(0.5moles* 1000)/(500ml)=1mole/L`

Therefore, the molarity of solution will be 1 M.