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Consider the following geometric sequence

-5,10,-20,40,...

If the reclusive formula for the sequence above is expressed in the form a^n = b*a^n-1 , determine the value of b

User Nablex
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1 Answer

3 votes

Hello from MrBillDoesMath!

Answer: b = -2

Discussion:

Let's analyze this sequence.

The first number = -5 a(0)

The second number = 10 = -5 (-2) a(1) = a(0) *-2

the third number = -20 = 10 * (-2) a(2) = a(1) * -2

The fourth number = -20 * (-2) a(3) - a(2) * -2


In other words, the recursive (not reclusive) formula is

a(0) = -5 (this need to be stated! Not stated in the problem)

a(n) = a(n-1) * (-2)

This implies that "b" = -2.


Regards, MrB

User Sanjeev Singh
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