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Find the equation for the line that passes through A's hypotenuse
plz show work

Find the equation for the line that passes through A's hypotenuse plz show work-example-1

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The answer is: " 1 "
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" y = -2x + 1 " .
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Step-by-step explanation:
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Look at the hypotenuse for "ΔA" and note the coordinates of where the hypotenuse crosses the "y-axis".

The coordinates are: " (0, 1) " ; that is: " x = 0 ; y = 1 " .

So, the problem /question is: " y = -2x + [?] " ;

→ Plug in " 1 " for "y" ; as follows:

→ " 1 = -2x + [?] " ;

→ We know that "x = 0";

→ when "x = 0" ; → " -2x " = " (-2 * 0) = 0 ;

So, 1 = 0 + [?] ;

The answer is " 1 " ; since: " { 0 + 1 = 1 .} .

Or, with a more detailed explanation:
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→ 1 = 0 + [?] ;

Subtract "0" from EACH SIDE of the equation;

→ 1 − 0 = 0 + [?] − 0 ;

to get:

→ 1 = [?] ;
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The answer is: " 1 " .
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User Tadiwanashe
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