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What is the square root of 18y over 36y to the third power? - I need to show work!

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\sqrt{(18y)/(36y^3)}=\sqrt{(18y)/(18y\cdot2y^2)}=\sqrt{(1)/(2y^2)}=(\sqrt1)/(√(2y^2))=(1)/(\sqrt2\cdot√(y^2))=(1)/(y\sqrt2)


(1)/(y\sqrt2)=(1)/(y\sqrt2)\cdot(\sqrt2)/(\sqrt2)=(\sqrt2)/(2y)
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