Question

Hey can you please help me posted picture of question

Answer 1

The solutions to the given quadratic equation can be determined using quadratic formula.


`x= \frac{-b+- \sqrt{ b^(2) -4ac} }{2a}`

b =coefficient of x term = -2
a = coefficient of squared term = 1
c = constant term = 10

Using the values in the above formula we get:


`x= (2+- √(4-4(1)(10)) )/(2(1)) \\ \\ x= (2+- √(-36) )/(2) \\ \\ x= (2+-6i)/(2) \\ \\ x=1+3i, x=1-3i`

So the correct answer to this question is option A