Answer:
Option D.
is the correct option.
Explanation:
Total number of solution sets n(S) (sample space) = 5×5 = 25
(Since a ping-pong ball can land on any block of the toss board so total number of events which can occur will be = 25)
Now preferred events n(E) = 5
(Since number of grey squares where ping-pong ball can land are = 5)
Therefore probability of landing of ping pong ball on a grey square P(E) =

P(E) =

P(E) =

Therefore, Option D.
will be the answer.