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What is the theoretical yield in liters of hydrogen at STP if 20.1g of calcium are completely reacted

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Calcium reacts with water to produce Calcium Hydroxide and Hydrogen gas;

Ca + 2 H₂O → Ca(OH)₂ + H₂

According to balance equation,

40 g (1 mole) Ca reacts to form = 22.4 L (1 mole) H₂
So,
20.1 g of Ca will produce = X L of H₂

Solving for X,,
X = (22.4 L × 20.1 g) ÷ 40 g

X = 11.25 L

Result:
Theoretical Yield of H₂ at STP = 11.25 Liter
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