Question

given that A=43 degrees , B=82 degrees and c=28, solve triangle ABC. Round to the nearest hundredth. A) C= 93 degrees , b= 33.8 , a= 23.3 B) C= 55 degrees , b= 33.8 , a= 23.3 C) C= 55 degrees , b= 23.3 , a= 33.8 D) C= 93 degrees , b= 23.3 , a= 33.8

Answer 1

The angles of the triangle can be determined by cosine law

a^2 = b^2 + c^2 - 2bccosA

substituting;
(43^2)=(82^2)+(28^2)-2(82)(28)cosA

A=23.3 degrees

and the other angles can be determined using sine law

sin A/ a = sin B/ b = sin C/ c


Thus,
B= 33.8 degrees
and
C= 55 degrees