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Using differentiation from first principles, prove that the gradient of the line y=mx + c is m

User AhabLives
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(dy)/(dx) = m
because when you differentiate, only the constant of the x remains (which is m in this case), and c being another constant independent of x, is 0 when differentiated. hence, since dy/dx is the gradient of the line, m is therefore the gradient
User Kezzos
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