Question

How many molecules of dinitrogen pentoxide are in 1.39 moles of dinitrogen pentoxide

Answer 1

1 mole of any substance has
`6.02*10^(23) particles. So, 1.39 mol N_(2)O_(5) have`


`1.39 mol * (6.02*10^(23))/(1 mol) =8.37*10^(23) molecules`

Answer 2

Step-by-step explanation:

According to Avogadro's number, it is known that there are
`6.023 * 10^(23)` atoms present in 1 mole of a substance.

Therefore, molecules or atoms present in 1.39 moles will be as follows.

No. of atoms = no. of moles × Avogadro's number

=
`1.39 moles * 6.023 * 10^(23)\text{atoms/mol}`

=
`8.37 * 10^(23)` atoms

Thus, we can conclude that there are
`8.37 * 10^(23)` atoms of dinitrogen pentoxide in 1.39 moles.