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How much heat, in kJ, is required to melt 54.0 g of ice at 0°C into water at 0°C if Hfus for water = 6.01?
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How much heat, in kJ, is required to melt 54.0 g of ice at 0°C into water at 0°C if Hfus for water = 6.01?

User Sagar Suri
by
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2 Answers

2 votes

18 that is what i think it is

User Grethe
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5.2k points
6 votes
The heat of fusion of 1 mole of water is 6.01 kJ/mol
1 mole of water is equal to 18 g
Therefore; 54,0 g of water is equivalent to 54/18 = 3 moles of water
Hence heat required;
= 3 × 6.01 = 18.03 kJ
User Dennis R
by
6.1k points
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