Question

A violin string playing the note "a" oscillates at 440 hz. what is the period of the string's oscillation? answer in units of s.

Answer 1

0.002272727

Step-by-step explanation:

1/440= 0.002272727

Answer 2

The frequency of a wave is equal to the reciprocal of its period:

`f= (1)/(T)`
where f is the frequency and T the period.

The violin string of our problem emits a note with frequency f=440 Hz, so if we re-arrange the previous equation, we can find the period of the string's oscillation:

`T= (1)/(f)= (1)/(440 Hz)=0.0023 s`