Question

How many total atoms are in 0.530 g of P2O5/12131141/dc2696ff?utm_source=registration

Answer 1

To find the number of atoms in 0.530 g of P2O5, you calculate the number of moles by dividing by the molar mass and then multiply by Avogadro's number, resulting in approximately 2.25 × 1021 atoms.

Step-by-step explanation:

To determine the number of atoms in 0.530 g of P2O5, we need to calculate the number of moles and then multiply by Avogadro's number (6.022 × 1023 atoms/mol). The molecular weight of P2O5 is found by adding the atomic weights of its constituent atoms: 2P (2 × 30.973761 amu/atom) + 5O (5 × 15.9994 amu/atom), which gives us approximately 141.94 amu. Since molar mass is the mass of one mole of a substance, we can say P2O5 has a molar mass of about 141.94 g/mol.

Now, to find moles, we divide the given mass by the molar mass:
0.530 g / 141.94 g/mol = 0.00373 mol.
Next, we multiply the moles by Avogadro's number to get the total atoms:
0.00373 mol × 6.022 × 1023 atoms/mol = 2.25 × 1021 atoms.

Answer 2

In order to calculate the number of atoms present in 0.53 grams of P₂O₅, first calculate the number of moles for given mass.

As, Moles is given as,

Moles = Mass / M.mass

Moles = 0.53 g ÷ 283.88 g.mol⁻¹

Moles = 0.00186 moles

Now calculate the number of Molecules present in calculated moles of P₂O₅.

As,
1 Mole of P₂O₅ contains = 6.022 × 10²³ Molecules
So,
0.00186 Moles of P₂O₅ contain = X Molecules

Solving for X,
X = (0.00186 mol × 6.022 × 10²³ Molecules) ÷ 1 mol

X = 1.12 × 10²¹ Molecules

Also, in P₂O₅ there are 7 atoms, in 1.12 × 10²¹ Molecules there will be.....

= 1.12 × 10²¹ × 7

= 7.84 × 10²¹ Atoms
Result:
7.84 × 10²¹ Atoms are present in 0.53 grams of P₂O₅.