Question

PLZ HELP ASAP FEAUTURES OF A CIRCLE FROM ITS STANDERED EQUATION

Answer 1

The general equation of the circle in standard form is:


`(x-a)^(2) + (y-b)^(2) = r^(2)`

The center of this circle is (a,b) and the radius is r.

Comparing it to the given equation, we get:

a = 0
b = 7.5
r² = 9/49

So, the center of given circle is (0, 7.5) and its radius is 3/7