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Second Geometry B question!

Second Geometry B question!-example-1

2 Answers

4 votes

Answer: Option D.) About 20%


7 votes
Let the length of the radius be x.
Area of the square = 4x²
Area of the circle = πx²
Area of the unshaded = 4πx² - πx² = x² (4 - π)


\text{P(unshaded)} = ( x^2(4- \pi ))/(4x^2) = (4- \pi )/(4) = 20\%

Answer: About 20%
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