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Second to last Geometry B problem!

Second to last Geometry B problem!-example-1

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Radius of the inner circle = 13.2 ÷ 2 = 6.6 mm
Area of the inner circle = π (6.6)² = 43.45π mm²

Radius of the larger circle = 6.6 + 4.4 = 11mm
Area of the larger cicle = π(11)² = 121π mm²

Area of the washer = 121π - 43.45π = 243.3 mm²

Answer: 243.3 mm²
User Eriola
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