Answer:
9, 10
Explanation:
let x be the larger integer and y the smaller
x × y = 7x + 20
y + 1 = x [consecutive]
substitute
(y + 1)y = 7(y + 1) + 20
y² + y = 7y + 7 + 20
y² + y - 7y - 7 - 20 = 0
y² - 6y - 27 = 0
(y - 9) (y + 3) = 0
y = 9
y = -3 [discarded as it must be a POSITIVE INTEGER]
y + 1 = x
9 + 1 = x
x = 10