Question

How many different ways can a club choose a committee of 4 from 15 members?

a.32,760
b.1,365
c.24

Answer 1

It is done by this formula

combinations = n! / [r! * (n - r)!]

combinations = 15! / [4! * 11!]
combinations = 15 * 14 * 13 * 12 * 11! / [4! * 11!]
combinations = 15 * 14 * 13 * 12 / 4 * 3 * 2
combinations = 15 * 7 * 13
combinations = 1,365

answer is b