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What are the values that satisfy the trigonometric equation for: 0≤q≤2π ? 0 ≤ q ≤ 2 π ? sin(∅)+tan(−∅)
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Dec 4, 2019
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What are the values that satisfy the trigonometric equation for: 0≤q≤2π ? 0 ≤ q ≤ 2 π ? sin(∅)+tan(−∅)
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Kevin Nielsen
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we have that
f(∅)=sin(∅)+tan(-∅)
for
0 ≤ ∅
≤ 2 π
using a graph tool
see the attached figure
the solutions are
∅=0
∅=pi
∅=2pi
Iiridayn
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Dec 11, 2019
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Iiridayn
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