Question

What is the area of triangle ABC

Answer 1

`\text{Area of triangle} = (1)/(2) ab \sin c`


`\text{Area of triangle} = (1)/(2) (40)(25) \sin(80)`


`\text{Area of triangle} = 492.4 \ m^2`

Answer 2

Area of triangle = 492 square meter.

Explanation:

Given : Triangle with two triangle AB and BC and angle B.

To find : What is the area of triangle ABC.

Solution : We have given Triangle with two triangle AB and BC and angle B.

By the formula

Area of triangle :
`(1)/(2)AB * BC * sin(B)`.

Plugging the values AB = 40 m , BC = 25 m

Area of triangle :
`(1)/(2) 40 * 25 * sin(80)`.

Area of triangle :
`(1)/(2) 40 * 25 * 0.984`.

Area of triangle = 492 square meter.

Therefore, Area of triangle = 492 square meter.