d=(x2−x1)2+(y2−y1)2
One pair of opposite sides are: KL and NM
KL=(4−−2)2+(6−3)2=45−−√=35–√
NM=(3−−3)2+(2−−1)2=45−−√=35–√
Using the substitution property KL=NM
The other pair is: KN and LM
KN=(−3−−2)2+(−1−3)2=17−−√
LM=(4−3)2+(6−2)2=17−−√
Using the substitution property KN=LM
Explanation:
KN=(−3−−2)2+(−1−3)2=17−−√
LM=(4−3)2+(6−2)2=17−−√