Question

The picture below shows a container that Rene uses to freeze water: A cylinder is shown with base diameter of 6 centimeters and the height as 8 centimeters. What is the minimum number of identical containers that Rene would need to make 2,000 cm3 of ice? (Use π = 3.14.) 27 9 14 20

Answer 1

it would be 9.

2000/226.2 = 8.84 == 9

Answer 2

9

Explanation:

Given : A cylinder is shown with base diameter of 6 centimeters and the height as 8 centimeters.

To Find: What is the minimum number of identical containers that Rene would need to make 2,000 cubic cm of ice.

Solution :

Diameter of container = 6 cm

Radius = Diameter/2 = 6/2 = 3 cm

Height of container = 8 cm

Volume of cylinder =
`\pi r^(2) h`

Where r is the radius

h is the height.

So, volume of the container =
`\pi* 3^(2) * 8`

=
`3.14* 3^(2) * 8`

=
`226.08`

Rene would need to make 2,000 cubic cm of ice.

So, no. of containers required =
`\frac{\text{Volume of ice}}{\text{Volume of container}}`

=
`(2000)/(226.08)`

=
`8.84`

So, no. of containers required = 8.84 ≈ 9.

Hence the minimum number of identical containers that Rene would need to make 2,000 cubic cm of ice is 9