Question

Line r passes through the point (3,6) and is parallel to line s is 3y=-6x+9 enter the equation of line r in y=ax+b form

Answer 1

y = -6/3 + 12

Explanation:

Step 1: Plot the point

Step 2: Simplify the given function then graph it

3y = -6x + 9 becomes:

y = -6/3x + 3

Step 3: Using the slope of -6/3 (because parallel lines will ALWAYS have the same slope) find 1 more point on the graph.

Step 4: Draw a line thru those points and find the y-int

y = ax + b, x and y are variables, a is the slope and b is the y-int

y = -6/3 + 12