Question

Calculate the molarity of the solution to 3 digits.

100. g of C12H22O11 (molecular weight = 342.28 g/mole) in 1.15 liters of solvent

Answer 1

The correct answer would be 0.254.

Answer 2

Answer: The molarity of the solution is 0.254 mol/L

Step-by-step explanation:

Molarity is defined as the number of moles of solute present per Liter of solution. It is a unit of concentration. The units used to express molarity is mol/L.

Mathematically,

`\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}*\text{Volume of solution (in L)}}`

We are given:

Given mass of solute = 100 g

Molar mass of solute = 342.28 g/mol

Volume of solution = 1.15 L

Putting values in above equation, we get:

`\text{Molarity of solution}=(100)/(342.28* 1.15)=0.254mol/L`

Hence, the molarity of the solution is 0.254 mol/L