Answer:
Explanation:
Given that Geoff has been given three points A, B, and C that are not on a line and he is trying to construct a circle that passes through all of the three points. So far he has created two line segments, AB and BC, found the perpendicular bisector of both segments, and found the intersection point of the two perpendicular bisectors
When three points are not collinear, they can form a circle.
For finding the circle, we must find a point which is equidistant from all the points. Perpendicular bisector intersection will have equal distance from all the 3 points.
Hence with centre as the point of intersection and radius as the point with any one of the three points, if we draw a circle, the circle will be the required circle.