Question

Solve the system of linier equations by A) Substitution, B) elimination

Answer 1

x=2 y=0
i hopes that helps

Answer 2

`5x + y = 10 \\ 2x - 6y = 4`
let's start with substitution. we will solve for one variable using one equation and then substitute j to the other equation. for example let's take the first equation and solve for y

`y = 10 - 5x`
now put this I to second formula

`2x - 6(10 - 5x) = 4 \\ 2x - 60 + 30x = 4 \\ 32x = 64 \\ x = 2`
now put this back into first equation

`5(2) + y = 10 \\ 10 + y = 10 \\ y = 0`
so we get x is 2 and y is 0

now we will save using elimination. to do this we wi multiply one equation so that we can add both equations and cancel out a variable
we will multiply the first equation. by 6

`6(5x + y = 10) \\ 30x + 6y = 60`
now we will add the two equations

`30x + 6y = 60\\ + 2x - 6y = 4 \\ 32x = 64 \\ x = 2`
you can do the same thing and cancel out x to find y.