Question

Find X with the Pythagorean Theorem

Answer 1

To find x (The hypotenuse) we must first find the missing leg.

`\left[\begin{array}{ccc}A^2+B^2=C^2\\\\Rearrange\;formula...\\\\A^2=C^2-B^2\\A^2=13^2-5^2\\A^2=169-25=144\\√(144)=12 \end{array}\right]`

Now we use 12 as our missing leg to find x (The hypotenuse)

`\left[\begin{array}{ccc}A^2+B^2=C^2\\35^2+12^2=C^2\\1225+144=1369\\√(1369)=37\end{array}\right]`

Your final answer is 37.

Answer 2

So, we have a multistep problem here.
We need to find side B of the triangle that is 13 and 5 to be able to find x.
5²+b²=13²
25+b²=169
169-25=144
b²=144
b=12
Now we know the side is 12, now we need to find x.
12²+35²=x²
144+1,225=x²
x²=1,369
x=37
So x=37