Question

Thomas and Kelsey are using a jump rope to model a typical wave. The wave they produce has a frequency of 4.2 hertz (Hz), an amplitude of 2.5 meters (m), and a wavelength of 5 m. What is the velocity, in meters per second (m/s), of this wave?

Answer 1

Thomas and Kelsey's wave has a velocity of 21 m/s, which is found by multiplying the frequency (4.2 Hz) by the wavelength (5 m).

Step-by-step explanation:

The velocity of a wave can be calculated using the formula velocity (v) = frequency (f) × wavelength (λ). In this case, Thomas and Kelsey have created a wave with a frequency of 4.2 Hz and a wavelength of 5 m. To find the velocity of their wave, we multiply the frequency by the wavelength:

v = f × λ
v = 4.2 Hz × 5 m
v = 21 m/s

Therefore, the velocity of the wave that Thomas and Kelsey produced is 21 meters per second (m/s).

Answer 2

The following expression shows the relationship between wavelength, velocity and frequency of a wave:

Wavelength [m] = Velocity [m/s] /frequency [Hz]

Making velocity the subject of the formula;

Velocity = Wavelength*Frequency = 5*4.2 = 21 m/s