171k views
4 votes
A jar contains four blue marbles and two red marbles. suppose you choose a marble at random, and do not replace it. then you choose a second marble. find the probability of each event to the nearest tenth of a percent.

a.the first marble is blue and the second is red
b.both marbles are blue

User GyroCocoa
by
9.0k points

2 Answers

3 votes
A) 26.7%
B) 40%

The probability of A is given by 4/6(2/5), since this is done without replacement; there are 4 blue marbles out of 6. When the first one is gone, there are 2 red out of 5 remaining.

The probability of B is given by 4/6(3/5), since this is done without replacement; there are 4 blue marbles out of 6. When the first one is gone, there are 2 blue out of 5 remaining.
User Critter
by
8.5k points
3 votes

Answer:

a)
(4)/(15)

b)
(2)/(5)

Explanation:

We are given the following information:

Number of red marbles in jar = 2

Number of blue marbles in jar = 4

Total number of marbles in jar = 6

Marbles are drawn from jar without replacement.

Formula:


\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

a) Probability(First marble is blue and second is red)

=Probability(Drawing a blue marble in first draw) × Probability(Drawing a red marble in second draw)


=(4)/(6)* (2)/(5)\\\\=(4)/(15)

b) Probability(First marble is blue and second is also blue)

=Probability(Drawing a blue marble in first draw) × Probability(Drawing a blue marble in second draw)


=(4)/(6)* (3)/(5)\\\\=(2)/(5)

User Prashant Thakre
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories